3sin^2x+4cosx=2

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Solution for 3sin^2x+4cosx=2 equation:


Simplifying
3sin2x + 4cosx = 2

Reorder the terms:
4cosx + 3in2sx = 2

Solving
4cosx + 3in2sx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3in2sx' to each side of the equation.
4cosx + 3in2sx + -3in2sx = 2 + -3in2sx

Combine like terms: 3in2sx + -3in2sx = 0
4cosx + 0 = 2 + -3in2sx
4cosx = 2 + -3in2sx

Divide each side by '4osx'.
c = 0.5o-1s-1x-1 + -0.75in2o-1

Simplifying
c = 0.5o-1s-1x-1 + -0.75in2o-1

Reorder the terms:
c = -0.75in2o-1 + 0.5o-1s-1x-1

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